# Simple problem

1. Jan 8, 2006

### Moneer81

Give a geometric argument to show that the graph of y = lxl has no tangent line at the point (0,0).

Since that graph would be basically the bisectors of the 1st and second quadrants, why can't the x-axis be that tangent line?
(def. of a tangent line is a line that touches the graph at one point, which is the origin in this case)

thanks

2. Jan 8, 2006

### d_leet

The slightly more correct definition of a tangent line at a point is the limit of secant lines through that point and one near it, as the nearer point approaches infinitely close to the point you want to find the tangent line to. If you do this for the function f(x) = |x| you'll notice what happens when you take points on both sides of the origin to draw secant lines through.

3. Jan 8, 2006

### Moneer81

so the x-axis doesn't qualify as a tangent line?

4. Jan 8, 2006

### d_leet

In a sense it is, but it doesn't fit the definition of a tangent line that they want you to use. I explained what they really want you to do in my previous post, and if you think about that you will see why there is no tangent line at x = 0.

5. Jan 8, 2006

### HallsofIvy

If that were the definition of tangent line, then every straight line through the origin would be a tangent line there. Check your text book for the specific definition of "the tangent line to a graph".