- #1

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The problem is from https://projecteuler.net/ if anyone is wondering.

## Homework Statement

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

## Homework Equations

## The Attempt at a Solution

Code:

```
#include <iostream>
using namespace std;
int main()
{
int num, add;
num = 1;
add = 0;
while(num < 1001)
{
if(num % 3 == 0 || num % 5 == 0)
{
add = num + add;
}
num = num + 1;
}
cout<<add<<endl;
return 0;
}
```