[SOLVED] simple projectile motion.. 1. The problem statement, all variables and given/known data A projectile is fired in such a way that its horizontal range is equal to 3 times its maximum height. What is the angle of projection? 2. Relevant equations whole bunch for proj motion. 3. The attempt at a solution I know that Dx = 3Dy. Let "t" be the time it takes for proj to reach max height. Dy = Vy*t (vertical) 3Dy = 2Vx*t (horizontal) Vy/Vx = (2t*dy)/(3t*dy) = 2/3 inverse tan (2/3) = 34 degrees, but the answer is 53.1 degrees. Any ideas what's wrong? Thanks.