- #1

- 251

- 0

how do I proof this?

I tried to do it by condradiction by assuming n is not a multiple of 6, i.e. when n is divided it is in the form of n = 1+k, or n = 2+k or n = 3+k or n = 4+k or n=5+k for some integer k

however I wasn't able to get anywhere, any help?