- #1
Exuro89
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- 1
Homework Statement
In Fig. 9.2, two blocks, of masses 2 kg and 3 kg, are connected by a light string that passes over a pulley of moment of inertia 0.004 kgm^2 and radius 5 cm. The coefficient of friction for the table top is 0.30. The blocks are released from rest. Using energy methods, one can deduce that after the upper block has moved 0.6 m, its speed is:
Homework Equations
Work Energy Theorum
The Attempt at a Solution
I know the answer to the problem is 1.4m/s but I'm not understanding why. This answer fits if the pulley is ignored with the equation
-F_fk = 1/2mv^2-mgh
But when I add the pulley in with this equation
-F_fk = 1/2mv^2+1/2Iw^2-mgh
the answer is wrong.
Does the term "passes over the pulley" mean the pulley is not rotating? So I would not need to put that into the equation? Thanks