Solve for all real x: (x^2-6x+9)^(x^2-4)=1
The Attempt at a Solution
I raised both sides by 1/x^2-4, so got x^2-6x+9=1, solved it to get x=2,4.
It's a question from a college enterance exam sample paper, so I wondered if it could be that simple. Is my Solution correct?