- #1

jimmy42

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Thanks.

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- Thread starter jimmy42
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- #1

jimmy42

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Thanks.

- #2

Doc Al

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What do you mean by "its horizontal force"?

- #3

jimmy42

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I know that the force acting in the Y direction, so up down will be different and can work that out. I just wanted to know if half the box is in the water does it follow that because half as much water is exposed to the box then the force is half as much as when it's fully in the water.

Thanks.

- #4

Doc Al

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The net horizontal force exerted by the water on the object will be zero. However the water does exert anSo, the water will be pushing on it in the positive and negative X ( left and right ) direction. If there is a box floating then only the bottom part will feel this force, as they are both equal they will cancel out. That means the box will not move.

The buoyant force equals the weight of the displaced liquid (this is Archimedes' principle). So the buoyant force when half-submerged is half as much as when fully submerged.I know that the force acting in the Y direction, so up down will be different and can work that out. I just wanted to know if half the box is in the water does it follow that because half as much water is exposed to the box then the force is half as much as when it's fully in the water.

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