# Simple question about e and ln.

1. Jan 23, 2008

### lemurs

Ok really dumb one here for you but for the life of me i can't remember.

first
e^(2lnx) is that equal to x^2

like i said brain fart
thanks for the help guys

2. Jan 23, 2008

### Midy1420

yup, e^(2lnx) = e^(ln (x^2)) = x^2

3. Jan 23, 2008

### rocomath

$$e^{2\ln x}$$

$$e^{\ln{x^2}}$$

$$x^2$$