a bar AB of no mass and 1m length is balanced on a support P at its midpoint. 0.6kg is hung on one end and 1kg is hung 0.3m away from the mid point on the other side. What is the upward force from support P
torque = perpendicular force * radius
The Attempt at a Solution
i thought it would be simple. i figured out the force on one side was 3N and the other side was the same. So 3N + 3N both acting down is 6 N since the bar isnt moving down it must be being pushed from the support with a force of 6N. However the answer in my book is 16N i don't understand how it can possibly be this.
Please show me where i went wrong.