Finding the Coefficient of Friction: A Simple Question on a 15 Degree Incline

[Mon0308]

Okay, so here's the simple question...I just can't seem to figure out what I am doing wrong so I won't elaborate on what I have done or not done...


At the *second an incline rises to 15 degrees, the 100kg box on it begins to slide.

What is the coefficient of friction?

*Note: the box does not move until the incline HITS 15 degrees, no more, no less.


That is the problem verbatim.


Any help would be great!

Thank You!

 

[Kurdt]

I'm afraid you will have to elaborate on what you've done if you wish to receive help. If it is a simple mistake it will be a lot easier for people helping to look at your working.

NOTE: You MUST show that you have attempted to answer your question in order to receive help. You MUST make use of the homework template, which automatically appears when a new topic is created in the homework help forums.

 

[baba89]

Hello, thank you for reaching out with your question. Finding the coefficient of friction can be a bit tricky, but here are some steps you can follow to determine the correct value:

1. First, we need to understand what coefficient of friction means. It is a measure of how much resistance there is between two surfaces when one is moving over the other. In this case, the two surfaces are the incline and the box.

2. We also need to know the formula for coefficient of friction, which is μ = F/N, where μ is the coefficient of friction, F is the force of friction, and N is the normal force between the two surfaces.

3. Now, let's consider the situation described in the question. The box begins to slide when the incline reaches 15 degrees. This means that the force of friction (F) is equal to the force of gravity pulling the box down the incline.

4. We also know that the normal force (N) is equal to the weight of the box, which is 100kg in this case.

5. Using the formula μ = F/N, we can plug in the values we know: μ = F/N = (100kg)(9.8m/s^2)/100kg = 9.8m/s^2.

6. Therefore, the coefficient of friction in this scenario is 9.8m/s^2.

It is important to note that the coefficient of friction can vary depending on the surfaces involved, so this value may not be the same for all situations. I hope this helps you understand how to find the coefficient of friction in this particular case. If you are still having trouble, feel free to provide more information on what you have tried so far, and I can assist you further. Good luck!