Simple Question on graphing

  • Thread starter Stripe
  • Start date
  • #1
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Homework Statement


A basketball is thrown into the air, and it's height is determined by

h = 3/4t(20-t) where t = time.


Homework Equations


What is the greatest height the ball reaches


The Attempt at a Solution


Ok so i tried to graph this out but stuffed up, a bit hard to show here.

So first i expanded the rule into
h=15t-3/4t^2
or
h=-3/4t^2+15t
Now i'm just wondering how i would graph that?
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
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31
you don't need to graph it, the maximum point occurs when dh/dt=0. So find the value of t for this height hmax
 
  • #3
32
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Ahh i see thanks a lot :D
 
  • #4
35,125
6,869

Homework Statement


A basketball is thrown into the air, and it's height is determined by

h = 3/4t(20-t) where t = time.


Homework Equations


What is the greatest height the ball reaches


The Attempt at a Solution


Ok so i tried to graph this out but stuffed up, a bit hard to show here.

So first i expanded the rule into
h=15t-3/4t^2
or
h=-3/4t^2+15t
Now i'm just wondering how i would graph that?
Since you posted this question in the Precalculus Math section, I assume that you haven't studied calculus just yet. The graph of the height function is a parabola that opens downward. You can find the vertex of the graph by completing the square, some exercises of which you did in another thread.

h = -3/4t2 + 15t
= -3/4(t2 - 20t)
= -3/4(t2 - 20t + 100) + 75
= -3/4(t - 10)2 + 75
 
  • #5
HallsofIvy
Science Advisor
Homework Helper
41,847
964
By the way, I started to reply that the graph was NOT a parabola but then realized I was interpreting what Stripe wrote incorrectly. I, and, I think, most people, would interpret "3/4t(20-t)" as 3/(4t(20-t)) which certainly is NOT a parabola and has no highest point.

Mark44 recognized that that could not correspond to a ball thrown upward and realized that Stripe meant y= (3/4)t(20-t).
 
  • #6
32
0
sorry about that it's hard trying to write equations on the computer lol
 
  • #7
32
0
= -3/4(t2 - 20t + 100) + 75
= -3/4(t - 10)2 + 75

So with that part where you completed the square, the + 75 is right because you do the opposide of -3/4 x 100?

Like i thought you were supposed to do the opposite of what's in the brackets, (-100) but i'm assuming because the -3/4 you instead do the opposite of -75?
 
  • #8
35,125
6,869
= -3/4(t2 - 20t + 100) + 75
= -3/4(t - 10)2 + 75

So with that part where you completed the square, the + 75 is right because you do the opposide of -3/4 x 100?

Like i thought you were supposed to do the opposite of what's in the brackets, (-100) but i'm assuming because the -3/4 you instead do the opposite of -75?
In the first expression, the 100 inside the parentheses is really -75, so to keep the expression equal I had to counter that by adding 75. The net effect is that I added -75 + 75 to that expression, which makes it exactly equal to what I started with.
 
  • #9
HallsofIvy
Science Advisor
Homework Helper
41,847
964
sorry about that it's hard trying to write equations on the computer lol

= -3/4(t2 - 20t + 100) + 75
= -3/4(t - 10)2 + 75

So with that part where you completed the square, the + 75 is right because you do the opposide of -3/4 x 100?

Like i thought you were supposed to do the opposite of what's in the brackets, (-100) but i'm assuming because the -3/4 you instead do the opposite of -75?
Parentheses! (-3/4) or -(3/4) not "-3/4". And use "^" to indicate powers. (-3/4)*(t- 10)^2 is far clearer than "-3/4(t-10)2"!

Yes, it is "+ 75" because (-3/4)(t^2- 20t+ 100)+ 75= (-3/4)t^2+ 15t- 75+ 75= (-3/4)t^2+ 15t.
 

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