- #1

WarPhalange

## Homework Statement

The problem is from an old GRE that I can't wrap my head around.

http://grephysics.net/ans/8677/94

## Homework Equations

V = -L(dI/dt)

I = V/R

## The Attempt at a Solution

Okay, so I have the solution, I just don't understand their reasoning. A change in current through an inductor makes it produce a voltage. I thought it was in the

*opposite*direction of where current was coming from, though, meaning that it would make the voltage across A

*smaller*at first and eventually let up and let the voltage go up to its asymptotic value.

Then when you closed the switch, I understand that the only way for the built up charge to dissipate is to make it go in a loop, through A, L, R2, and the Diode. I don't understand why it doesn't all just go directly from L to Ground?