- #1
fisselt
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I know I've done this problem a few times before but I'm just a fumbling idiot at the moment..
Rocket has an acceleration of 12m/s^2 and at an altitude of 1km the motor shuts off. What is the maximum height?
V^2=V_i+2a(x_f-X_i)
x_f=x_i+V_i(t)+1/2at^2
V^2=0+2(12)(1000)=154.92m/s
0=154.92t-9.8t^2, t=17.213s
x_f=1000+154.95(17.213)-1/2(9.8)(17.213)^2=2214.82meters
I feel like I'm doing it wrong. 12m/s^2 is the acceleration of the motor, shouldn't their be some force from gravity on the rocket while going towards 1000m?
Thanks for the help.
Homework Statement
Rocket has an acceleration of 12m/s^2 and at an altitude of 1km the motor shuts off. What is the maximum height?
Homework Equations
V^2=V_i+2a(x_f-X_i)
x_f=x_i+V_i(t)+1/2at^2
The Attempt at a Solution
V^2=0+2(12)(1000)=154.92m/s
0=154.92t-9.8t^2, t=17.213s
x_f=1000+154.95(17.213)-1/2(9.8)(17.213)^2=2214.82meters
I feel like I'm doing it wrong. 12m/s^2 is the acceleration of the motor, shouldn't their be some force from gravity on the rocket while going towards 1000m?
Thanks for the help.