- #1
Tom1
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Homework Statement
Solve the initial value problem:
y''+2y'+2y=0
y([tex]\pi[/tex]/4)=2
y'([tex]\pi[/tex]/4)=-2
Homework Equations
Included in 1
The Attempt at a Solution
I assumed that y=e^rt and came up with the characteristic polynomial r^2+2r+2=0 but when solving it for the two roots, they come back as non-real. Where have I gone wrong? thanks