- #1

- 58

- 0

**[SOLVED] Simple Self-Inductance Problem**

**1. Homework Statement**

Find the inductance L of a long solenoid of length 39.0 cm, and radius 2.30 cm, which has 3.10E2 turns. (Express you answer in units of H for henrys).

**2. Homework Equations**

[tex]L=\frac{N\Phi_{B}}{i}[/tex]

[tex]\Phi_{B}=BA=\frac{\mu_{0}NiA}{2\pi*r}[/tex]

**3. The Attempt at a Solution**

Okay, so the way I am thinking to solve this problem is to first get the magnetic flux. But I have no idea how to find the current [tex]i[/tex] for a solenoid. Since I don't know how to find [tex]i[/tex], I simply plugged in the formula for flux into the formula for inductance to get:

[tex]L=\frac{N\Phi_{B}}{i}=\frac{\mu_{0}N^{2}A}{2\pi*r}[/tex]

That's where I get stuck. *If* I am in fact going about this the right way, do I just find area by using pi*r^2?