A mass of 3.15 kg stretches a vertical spring 0.290 m. If the spring is stretched an additional 0.197 m and released, how
long does it take to reach the (new) equilibrium position again?
The Attempt at a Solution
First I solved for k using F=kx where F is the weight of the mass
Then I solved for the period, T...
and the time required to reach equilibrium would be half a period so T/2 right?