1. The problem statement, all variables and given/known data A mass of 3.15 kg stretches a vertical spring 0.290 m. If the spring is stretched an additional 0.197 m and released, how long does it take to reach the (new) equilibrium position again? 2. Relevant equations F=-kx T=2(pi)(m/k)^.5 3. The attempt at a solution First I solved for k using F=kx where F is the weight of the mass mg=kx Then I solved for the period, T... T=2(pi)(m/k)^.5 and the time required to reach equilibrium would be half a period so T/2 right?