Hi PF I have a statics problem that i solve. BUT I’m insecure rather or not it is solved correctly. The mechanical system is shown in the link below http://peecee.dk/upload/view/340798 A weight less wire is supsended from the wall in point C and attached to a heavy bar at point A. The other end of the bar is attached to the wall but can move in the vertical direction. The weight of the bar is F_g. All other dimensions known are given in the figure. The aim is to find the force P required to push the bar down, so that the bar is in a horizontal position. My solution: First, the outer forces are noted http://peecee.dk/upload/view/340799 A force balance in the x direction gives R_bx=R_cx In the y diection -P-F_g+R_cy=0 Moment balance around point C, anti clockwise being positive gives, -R_bx*(h-sin(alpha)*l)+F_g*(h-sin(alpha)*l*1/2)=0 ⇔ R_bx=F_g*(h-sin(alpha)*l*1/2)/ (h-sin(alpha)*l) .. (eq1) The main system is cut into two subsystems as shown in the link http://peecee.dk/upload/view/340800 A force balance on the wire gives R_cx=R_ax R_ay=R_cy And then a force balance on the bar. in the x direction: R_bx=R_ax In the y direction: R_ay-F_g-P=0 And moment around point A gives: -F_g*1/2*l*cos(alpha)+R_bx*l*sin(alpha)-P*l*cos(alpha)=0 ⇔ P= (-F_g*1/2*l*cos(alpha)+R_bx*l*sin(alpha))/(l*cos(alpha)) .. (eq2) Using (eq1) in (eq2) gives an expression for P as: P= -(1/2)*F_g*(-cos(alpha)*h+cos(alpha)*sin(alpha)*l+2*sin(alpha)*h-sin(alpha)^2*l)/(cos(alpha)*(-h+sin(alpha)*l)) Inserting reasonable values for h, l and alpha and F_g in the expression for P also gives reasonable results. However, I'm very much in doubt rather or not the moment in the main system is possible to do due to the boundary conditions (eq1). I on the other hand don’t see any solution Any help is appreciated.