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Simple Trig Question

  1. May 23, 2009 #1
    Hi,

    I'm just stumped on how to solve the following type of trig equation. Could someone show working / a tutorial on how to solve similar equations. I'm fine with simple ones like: 4 + sinx = 3 , but this style has me stumped:

    sin(x + 30) = 1
    or

    tan(x + 45) = 1

    Thanks!
     
  2. jcsd
  3. May 23, 2009 #2

    Gib Z

    User Avatar
    Homework Helper

    Try letting u = x + 30 in the first one, or u= x+45 in the second one. Then, solve it just like you are used to and you attain your values for u. You know the relation between u and x, easy. =]

    EDIT: I didn't realize this wasn't the homework forum when I posted. From now on, please only ask homework style questions in the Homework Help forum.
     
  4. May 24, 2009 #3
    sin(x + 30) = 1

    ( x + 30 ) = 90

    x = 90 - 30

    x = 60
     
  5. May 24, 2009 #4
    x = 60 + 2k pi

    edit: oh wait, in degrees that is:
    x = 60 + 360k

    Where k is any whole number.

    Because sine is repetitive every 360 deg or 2pi rad.
     
  6. May 24, 2009 #5
    opps yea you are right ,forgot to include that =.=
     
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