1. The problem statement, all variables and given/known data -sin x = √3 * cos x where x is [0,2π] 2. Relevant equations 3. The attempt at a solution Would it be wrong to square both sides and then factor? sin2 x = 3cos2 x 1-cos2 x = 3cos2 x 0= 4cos2 x - 1 0 = (2cos x -1)(2cos x + 1) Now I solve the factors (2 solutions for each) Since I've squared both sides, haven't I introduced extra solutions that are not part of the original problem? Will all 4 resulting solutions be correct? Thanks.