(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

-sin x = √3 * cos x

where x is [0,2π]

2. Relevant equations

3. The attempt at a solution

Would it be wrong to square both sides and then factor?

sin^{2}x = 3cos^{2}x

1-cos^{2}x = 3cos^{2}x

0= 4cos^{2}x - 1

0 = (2cos x -1)(2cos x + 1)

Now I solve the factors (2 solutions for each)

Since I've squared both sides, haven't I introduced extra solutions that are not part of the original problem? Will all 4 resulting solutions be correct? Thanks.

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# Simple Trig Question

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