- #1

- 222

- 0

The position of a particle as a function of time given by:

**r**=(5i^+4j^)t^2m , where t is in seconds. Find an expression for the particles velocity

**v**as a function of time.

Where I wrote the ^ after the letters means its a unit vector.

Now isn't the way that one would find the velocity is to take the derivative of the expression? Or is that just for instantanious velocity? And if the way to find to velocity is to take the derivative, do I first distribute the t^2 then differentiate, ending up with: f'(t)=(10ti^+8tj^)m/s? Or do I use the product rule and end up with: f'(t)=(9t^2+10ti^+8tj^)m/s?