# Simple Vector Alegebra Problem

• JoshHolloway
Can you explain it more clearly?In summary, the conversation is about a problem from a physics course where the position of a particle is given as a function of time. The question is to find the expression for the particle's velocity as a function of time. The solution is to take the derivative, using either the distributive property or the product rule. The final answer is v = (10ti^+8tj^)m/s.

#### JoshHolloway

Hello all. I have a problem from my homework that I can't seem to figure out. It is a problem from a freshman introductory physics course. Here goes:
The position of a particle as a function of time given by: r =(5i^+4j^)t^2m , where t is in seconds. Find an expression for the particles velocity v as a function of time.

Where I wrote the ^ after the letters means its a unit vector.
Now isn't the way that one would find the velocity is to take the derivative of the expression? Or is that just for instantanious velocity? And if the way to find to velocity is to take the derivative, do I first distribute the t^2 then differentiate, ending up with: f'(t)=(10ti^+8tj^)m/s? Or do I use the product rule and end up with: f'(t)=(9t^2+10ti^+8tj^)m/s?

You take the derivatve. It doesn't matter if you distribute first, the coefficient of $t^2$ is a constant.

So the answer is v = f'(t) = (10ti^+8tj^)m/s ?

yup.
additional charaters to make the post 10 characters long

LeonhardEuler said:
additional charaters to make the post 10 characters long

I don't understand what you mean by this.