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Homework Help: Simple Vector problem

  1. Oct 3, 2007 #1
    1. The problem statement, all variables and given/known data
    A car proceeding due south at 60 km/h (V1) makes a right turn, after which it is traveling due west at 80 km/h (V2). What is its change in velocity (V2-V1)?

    2. Relevant equations

    3. The attempt at a solution
    I obviously did 80 km/h - 60 km/h = + 20 km/h. However this is wrong. I don't see why, but it is wrong. The instructor mentioned solving this geometrically or something like that, but I have no clue what they're talking about.
  2. jcsd
  3. Oct 3, 2007 #2

    D H

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    You are confusing velocity (a vector quantity) with speed (a scalar quantity). Its an easy trap to fall into as we use the two terms colloquially to mean the same thing. I assume your instructor wants you to compute the magnitude of the change in the velocity vector, so in a sense he has been caught in the same trap.

    Can you compute v2-v1 as a vector and then take its magnitude?
  4. Oct 3, 2007 #3


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    You need to read about vectors in your course materials. Velocity is a vector; it has both magnitude and direction. If we take east as the positive x direction, and north as the positive y direction, then the x component of V1 is 0, and the y component is -60 km/h. I could also specify V1 by its magnitude (60 km/h), and by the angle an arrow pointing in the direction of motion makes with the positive x axis (90 degrees, or pi/2 radians).
  5. Oct 3, 2007 #4

    So basically it means,

    (-80 km/h West) - (-60 km/h South) = -20 km/h

  6. Oct 3, 2007 #5

    D H

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    First, why did you add those negative signs, and second, why did you throw away the directions?

    I'm going to ask a different question: A car travels due south 60 km, turns to the west, and travels another 80 km. How far is the car from the starting point?

    The answer is not 140km, nor 20km, nor anything like that. Don't throw away the directional information because that is one of the two things that make a vector a vector.
  7. Oct 5, 2007 #6
    I added those negative signs because in vectors south and west are considered negative in terms of magnitude? And I didn't throw away the directions? What did you mean? I mentioned the course of direction for each vector.

    (-60 km due south)i + (-80km due west)j = -140 km due south west

    http://www.glenbrook.k12.il.us/GBSSCI/PHYS/CLASS/1DKin/U1L1d.html [Broken]
    Last edited by a moderator: May 3, 2017
  8. Oct 5, 2007 #7


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    Are you just trying things at random now? You "mention" the course of direction but do nothing at all with it! Also, by the way, the units are NOT "km", they are "km/hr". YOU said that this was a vector problem. Why haven't you used vectors at all?

    Draw a picture. Draw a vector "60 km/h" due south. In other words, pick some convenient scale (say a cm for each 10 km/h) and take "due south" to mean "down" on your paper. You have a line segment (arrow) 6 cm long going down. At the origin (beginning point) of that arrow, draw another "80 km/h due West". That would be a line segment (arrow) 8 cm long pointing to the left. Now draw the segment connecting the origin of the tips of the two arrows. That vector is their difference. You will need to give both its length (that's easy- think "3-4-5" right triangle) and the angle it makes (a bit harder- you will need trig functions).
  9. Oct 5, 2007 #8

    D H

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    Mea culpa! I thought Henry might be able to deal with the slightly different and more concrete problem of adding displacement vectors. My hope was that he would have readily answered my question in post#5. My plan was to then move him back to the original problem of adding velocity vectors. The best laid plans ...

    Henry, please follow Halls' advice. Draw a picture.
  10. Oct 5, 2007 #9
    I believed this might have been mentioned... You have to make a triangle with the vectors... Vectors are drawn head to tail... So your resulting Vector will point South West... You can use pythagorean theorem to find the resulting velocity... very difficult to explain vectors without drawing diagrams :(
  11. Oct 6, 2007 #10
    Why would I need to make a triangle when the problem is only asking for the change in velocity, it's not asking for the resultant. But i'll do that anyways. I'll post it tommorow.
  12. Oct 6, 2007 #11


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    Because the change in velocity is (directly related to) the magnitude of the resultant :)
  13. Oct 6, 2007 #12
    You beat me to it. :)
  14. Oct 8, 2007 #13
    Would I use the avg velocity to find the change in velocity?

    with the change in distance over time?

    (-80 km) west - (-60 km) south / 2h - 0 h


    -20km/2h = -10 km/h due south west?

    is this right?
  15. Oct 8, 2007 #14

    D H

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    Why are you refusing to do what everyone here has asked you to do, which is draw a picture? This is a vector problem, you need to use vectors. You have'nt done that yet.

    To answer your question, the result in post #13 is not right.
  16. Oct 8, 2007 #15
    I drew it. So am I suppose to find the resultant? Or...?

    Attached Files:

  17. Oct 8, 2007 #16

    D H

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    That drawing is not quite right. It shows how to graphically compute V1+V2 (the vector along the hypotenuse). You want V2-V1. At least you have the magnitude correct now.
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