If a force vector has a magnitude of 4.82 Newtons and points 42.3 degrees south of east, then what is its x-component?
x = |v| cos(theta)
y = |v| sin(theta)
The Attempt at a Solution
Since the problem states that the vector's deviation is 42.3 degrees south of east, the actual angle is the sum of 90 degrees and 42.3 degrees, 132.3 degrees. Then to find the x component I multiply the length of the vector, and the cosine of the angle. However the answer that I get, -3.24392032 is not right. Any help would be appreciated.