A rope exerts a constant horiztonal force of 250N to pull a 60kg crate across the floor. The velocity of the crate is observed to increase from 1m/s to 3m/s in a time of 2 seconds under the influence of this force and the frictional force exerted by the floor on the crate
A) what is the accleration of the crate?
b) what is the netforce acting on the crate?
c) what is the magnitude of the frictional force acting on the crate?
As stated in the attempt
The Attempt at a Solution
a) because of the given information i use the difference in velocity by time to produce a result of 1m/s. I am not sure if i should be a = fnet/mass
b) i use the eq force = ma, 60kg * 1m/s = 60N
c) This is where i am having difficulty, i know for the accleration to be 1m/s, the equation would ultimatey have to be a = fnet/mass = 60n/60kg. subtracting 60n from the 250 yeilds the number, 190, which is the one i need to subtract from the given force to get 60. but i am having a hard time understanding how a 60N force on a crate can produce 130n in friction? Am i way off with my attempts?
Thank you for your help.