Well, n is a common factor so can you start yourself?
After that, it'll be a bit harder to find factors but still doable (by finding zeroes of the polynomial!).
Try factoring out n yourself ?
#5
thanks for the fast reply!
I have tried to get the roots (the zeros). After taking n as a common factor we have:
n(6n^4+15n^3+10n^2-1)
" 6n^4+15n^3+10n^2-1" has 4 roots and two of them are "strange" (dont know a better word). what i mean by strange is that one is unable to write them as 1/2, 1/3 or x/y.
the value of the root is: -1.263763...
the other root is: 0,263763...
does anyone know how to deal with these kind of problems
If a is a zero, then you can factor out (x-a)
Try adding up all coëfficiënts of the even powers in x and the ones of the odd powers in x, if these 2 are the same then -1 is a zero and thus, (x+1) a factor.
#7
Thanks TD for your very fast replies
By taking the roots i get the simplification:
(x+1.263763...)(x+1)(2x+1)(x-0,263763...)
I did not understand what u mean (i have the same powers for all x (=1), or?)
However, can i by any method cancel the 0.263763...