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Simplify a expression

  • Thread starter rover
  • Start date
  • #1
rover
Hi,
Could someone help me to simplify this expression:

6n^5+15n^4+10n^3-n

Thanks,

:smile:
 

Answers and Replies

  • #2
TD
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You can start by factoring out n :smile:
 
  • #3
rover
I forgot to mention that it should be in the form of:
n(n+1)(.........

thanks
 
  • #4
TD
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Well, n is a common factor so can you start yourself?
After that, it'll be a bit harder to find factors but still doable (by finding zeroes of the polynomial!).

Try factoring out n yourself ?
 
  • #5
rover
thanks for the fast reply!

I have tried to get the roots (the zeros). After taking n as a common factor we have:
n(6n^4+15n^3+10n^2-1)

" 6n^4+15n^3+10n^2-1" has 4 roots and two of them are "strange" (dont know a better word). what i mean by strange is that one is unable to write them as 1/2, 1/3 or x/y.

the value of the root is: -1.263763........
the other root is: 0,263763........

does anyone know how to deal with these kind of problems
 
Last edited by a moderator:
  • #6
TD
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If a is a zero, then you can factor out (x-a)
Try adding up all coëfficiënts of the even powers in x and the ones of the odd powers in x, if these 2 are the same then -1 is a zero and thus, (x+1) a factor.
 
  • #7
rover
Thanks TD for your very fast replies

By taking the roots i get the simplification:

(x+1.263763....)(x+1)(2x+1)(x-0,263763......)

I did not understand what u mean (i have the same powers for all x (=1), or?)
However, can i by any method cancel the 0.263763......
 
  • #8
Hurkyl
Staff Emeritus
Science Advisor
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I forgot to mention that it should be in the form of:
n(n+1)(.........
Then, you should be able to divide your original polynomial by n(n+1) and see what's left.

By the way, "strange" is irrational.
 
  • #9
rover
I solved it!! :smile: :rofl: :rolleyes:

if you multiply those irrational numbers you get a rational value!!!
The simplified answer is

x(x+1)(2x+1)(3x^2+3x-1)
 

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