- #1

rover

Hi,

Could someone help me to simplify this expression:

6n^5+15n^4+10n^3-n

Thanks,

Could someone help me to simplify this expression:

6n^5+15n^4+10n^3-n

Thanks,

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- Thread starter rover
- Start date

- #1

rover

Hi,

Could someone help me to simplify this expression:

6n^5+15n^4+10n^3-n

Thanks,

Could someone help me to simplify this expression:

6n^5+15n^4+10n^3-n

Thanks,

- #2

TD

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You can start by factoring out **n**

- #3

rover

I forgot to mention that it should be in the form of:

n(n+1)(.........

thanks

n(n+1)(.........

thanks

- #4

TD

Homework Helper

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After that, it'll be a bit harder to find factors but still doable (by finding zeroes of the polynomial!).

Try factoring out

- #5

rover

thanks for the fast reply!

I have tried to get the roots (the zeros). After taking n as a common factor we have:

n(6n^4+15n^3+10n^2-1)

" 6n^4+15n^3+10n^2-1" has 4 roots and two of them are "strange" (dont know a better word). what i mean by strange is that one is unable to write them as 1/2, 1/3 or x/y.

the value of the root is: -1.263763........

the other root is: 0,263763........

does anyone know how to deal with these kind of problems

I have tried to get the roots (the zeros). After taking n as a common factor we have:

n(6n^4+15n^3+10n^2-1)

" 6n^4+15n^3+10n^2-1" has 4 roots and two of them are "strange" (dont know a better word). what i mean by strange is that one is unable to write them as 1/2, 1/3 or x/y.

the value of the root is: -1.263763........

the other root is: 0,263763........

does anyone know how to deal with these kind of problems

Last edited by a moderator:

- #6

TD

Homework Helper

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Try adding up all coëfficiënts of the even powers in x and the ones of the odd powers in x, if these 2 are the same then -1 is a zero and thus, (x+1) a factor.

- #7

rover

By taking the roots i get the simplification:

(x+1.263763....)(x+1)(2x+1)(x-0,263763......)

I did not understand what u mean (i have the same powers for all x (=1), or?)

However, can i by any method cancel the 0.263763......

- #8

Hurkyl

Staff Emeritus

Science Advisor

Gold Member

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I forgot to mention that it should be in the form of:

n(n+1)(.........

Then, you should be able to

By the way, "strange" is irrational.

- #9

rover

if you multiply those irrational numbers you get a rational value!!!

The simplified answer is

x(x+1)(2x+1)(3x^2+3x-1)

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