- #1

- 2

- 0

My own answer is (n+1)^2/n^2, but its apparently wrong

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- Thread starter Helge
- Start date

- #1

- 2

- 0

My own answer is (n+1)^2/n^2, but its apparently wrong

- #2

- 252

- 1

[tex]

\frac{(n+1)^{2}\cdot n!}{(n+1)!\cdot n^{2}}

=

\frac{(n+1)^{2}\cdot n!}{(n)!\cdot(n+1) \cdot n^{2}}

=

\frac{(n+1)\cdot n!}{(n)! \cdot n^{2}}

=

\frac{(n+1)}{n^{2}}

[/tex]

All you had to do was expand the (n+1)! into (n+1)n!.

:)

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