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Simplifying factorials

  1. Nov 16, 2011 #1
    How can ((n+1)^2(*n!))/((n+1)!*n^2) be simplified to (n+1)/n^2?

    My own answer is (n+1)^2/n^2, but its apparently wrong
     
  2. jcsd
  3. Nov 16, 2011 #2
    Here's how:

    [tex]
    \frac{(n+1)^{2}\cdot n!}{(n+1)!\cdot n^{2}}
    =
    \frac{(n+1)^{2}\cdot n!}{(n)!\cdot(n+1) \cdot n^{2}}
    =
    \frac{(n+1)\cdot n!}{(n)! \cdot n^{2}}
    =
    \frac{(n+1)}{n^{2}}

    [/tex]

    All you had to do was expand the (n+1)! into (n+1)n!.

    :)
     
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