- #1

- 2

- 0

## Main Question or Discussion Point

How can ((n+1)^2(*n!))/((n+1)!*n^2) be simplified to (n+1)/n^2?

My own answer is (n+1)^2/n^2, but its apparently wrong

My own answer is (n+1)^2/n^2, but its apparently wrong

- Thread starter Helge
- Start date

- #1

- 2

- 0

How can ((n+1)^2(*n!))/((n+1)!*n^2) be simplified to (n+1)/n^2?

My own answer is (n+1)^2/n^2, but its apparently wrong

My own answer is (n+1)^2/n^2, but its apparently wrong

- #2

- 252

- 1

[tex]

\frac{(n+1)^{2}\cdot n!}{(n+1)!\cdot n^{2}}

=

\frac{(n+1)^{2}\cdot n!}{(n)!\cdot(n+1) \cdot n^{2}}

=

\frac{(n+1)\cdot n!}{(n)! \cdot n^{2}}

=

\frac{(n+1)}{n^{2}}

[/tex]

All you had to do was expand the (n+1)! into (n+1)n!.

:)

- Replies
- 13

- Views
- 1K

- Last Post

- Replies
- 2

- Views
- 2K

- Last Post

- Replies
- 5

- Views
- 2K

- Last Post

- Replies
- 1

- Views
- 13K

- Last Post

- Replies
- 3

- Views
- 6K

- Last Post

- Replies
- 12

- Views
- 795

- Last Post

- Replies
- 2

- Views
- 2K

- Last Post

- Replies
- 2

- Views
- 439

- Last Post

- Replies
- 24

- Views
- 4K

- Last Post

- Replies
- 1

- Views
- 3K