- #1

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is it possible to simplify this more?!?!

Ln(log

Ln(log

Ln(log

_{7}-log_{7}6)=Ln(log

_{7}7)- Thread starter skelitor413
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- #1

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is it possible to simplify this more?!?!

Ln(log_{7}-log_{7}6)=

Ln(log_{7}7)

Ln(log

Ln(log

- #2

symbolipoint

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To start with, some of that does not look correct. You are missing the antilog in one of your "log" expressions. (logis it possible to simplify this more?!?!

Ln(log_{7}-log_{7}6)=

Ln(log_{7}7)

- #3

symbolipoint

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- #4

HallsofIvy

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Persumably you mean ln(logis it possible to simplify this more?!?!

Ln(log_{7}-log_{7}6)=

Ln(log_{7}7)

Yes, ln(log

Further, by the very definition of log, log

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