Understanding the Error in Simpson's 1/8 Integration Method

In summary, the conversation discusses an error in Simpson's rule for integration when using Langrane/Newton of order 2. The error should result in f^3(c) but it is cancelled out when going from -1 to 1. The referenced link is not accessible for everyone, but it can be found by searching for "Simpson's error, derivation" on the JSTOR website. The conversation also mentions restarting a computer to resolve the issue.
  • #1
rootX
479
4
[SOLVED] Simpson 1/8 Integration

How does it has an error of h^5 * f^4(c)/90
when Langrane/Newton of order 2 is used to derive this,
and you should get f^3(c) as an error?
 
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  • #2
f^3 cancel out if you go from -1 to 1
I was using t as 0 1 2
http://www.jstor.org/sici?sici=0025-5572(197010)2%3A54%3A389%3C292%3A3ASDOT%3E2.0.CO%3B2-1&cookieSet=1
 
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  • #3
Your link doesn't work. At least not for me.
 
  • #4
It does work for me :D
It just an online book where they have derivation for the Simpson error.
 
  • #5
It might work for you, but that doesn't mean it will work for everybody. I get "An Error Occurred Setting Your User Cookie" using firefox in linux. It's really best to avoid links if you want everyone to be able to see the problem.
 
  • #7
Dick said:
It's really best to avoid links if you want everyone to be able to see the problem.
That's a solution though :rolleyes:
 

What is Simpson 1/8 Integration?

Simpson 1/8 Integration is a numerical method used for approximating definite integrals. It is based on dividing the interval of integration into smaller subintervals and using a quadratic polynomial to approximate the curve within each subinterval. This method is more accurate than the trapezoidal rule and is commonly used in scientific and engineering applications.

How does Simpson 1/8 Integration work?

To use Simpson 1/8 Integration, the interval of integration is divided into an even number of subintervals. Then, a quadratic polynomial is fit to each pair of adjacent subintervals. The integral of the polynomial within each pair of subintervals is then calculated and summed to approximate the overall integral of the function over the entire interval. The accuracy of the approximation increases as the number of subintervals increases.

What are the advantages of using Simpson 1/8 Integration?

Simpson 1/8 Integration is more accurate than the trapezoidal rule and requires fewer subintervals to achieve the same level of accuracy. It also has a faster convergence rate, meaning that the approximation approaches the true value of the integral more quickly. Additionally, it can be used for functions with more complex shapes and does not require the function to be continuous.

What are the limitations of Simpson 1/8 Integration?

Simpson 1/8 Integration can only be used for definite integrals and requires the function to have a continuous second derivative. It also does not perform well for functions with sharp corners or discontinuities. In these cases, a different numerical method may be more appropriate.

How do you calculate the error of Simpson 1/8 Integration?

The error of Simpson 1/8 Integration can be calculated using the error formula: E = (b-a)(h^5/90)*f^(4)(c), where a and b are the limits of integration, h is the width of each subinterval, and f^(4)(c) is the fourth derivative of the function evaluated at some point c within the interval of integration. The error decreases as the number of subintervals increases, and the approximation approaches the true value of the integral.

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