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Simultaneous eigenstate of angular momentum and hamiltonian
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[QUOTE="davon806, post: 5756516, member: 439351"] [B]1.[/B]I don't know what Π_1 is representing , I mean,like position and momentum operator you have Xψ = xψ , Pψ = -ih d/dx ψ ,but here you have got something like ΠXΠ^-1 = -X which is not the usual form of Kψ = kψ. Then what can I do to compute [ H,Π } ? [B]2.[/B]Since L_3 is acting in the z-direction, Π L_3 ∏^-1 = L_3 ? so Π L_3 = L_3 Π and L_3 Π | E,m> = Π L_3 | E,m> = m Π | E,m> ? However ,the question said Π X ∏^-1 is valid for position and momentum operator, but here we are dealing with angular momentum operator? [/QUOTE]
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Simultaneous eigenstate of angular momentum and hamiltonian
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