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How do you solve:

ln(1-x) = a(b-1/T)

ln(x) = c(d-1/T)

for x and T ?

I see that x = e^c(d-1/T) and 1 = e^a(b-1/T) + e^c(d -1)/T but it is unclear to me what substitution to try next.

Thanks

cvr

ln(1-x) = a(b-1/T)

ln(x) = c(d-1/T)

for x and T ?

I see that x = e^c(d-1/T) and 1 = e^a(b-1/T) + e^c(d -1)/T but it is unclear to me what substitution to try next.

Thanks

cvr

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