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Simultaneous Equations

  1. May 3, 2012 #1
    I have the following simultaneous equations. However I am unsure how to handle that 2xy. Can someone give a pointer to any known methods?

    x= 3x^2+2xy
    y=x^2+3y+8
     
  2. jcsd
  3. May 3, 2012 #2
    Just factor out the first equation so you can get x(1-3x-2y)=0 and then you transform the equation.
     
  4. May 3, 2012 #3

    Borek

    User Avatar

    Staff: Mentor

    Second equation is linear in y, so you can solve by substitution.
     
  5. May 3, 2012 #4
    After you have x(1-3x-2y)=0, you will then have to split that up with what you know about a*b=0.
     
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