# Simultaneous linear equation

1. Sep 2, 2010

### Loke

1. The problem statement, all variables and given/known data
Find value L and X.

0.182(L2+X2)=1602
0.182[(555.56+L)2+X2]=2402

2. Sep 2, 2010

### eumyang

Technically, these aren't linear equations, are they, since both L and X are squared. You can solve this through substitution. I would solve the 1st equation for X2, then substitute the result into the 2nd equation and then solve for L. Try it, and let us know what you get.

69

3. Sep 2, 2010

### Loke

but i still dont know why i cant solve it out ....can you show me how you do it? ^^

4. Sep 2, 2010

### HallsofIvy

Well, what have you tried to do? Have you solved $0.18^2(L^2+ X^2)= 160^2$? If so, what did you get?

What equation do you get when you replace $X^2$ by that in $0.182[(555.56+L)^2+X^2]=2402$?