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Compute [tex]\int^{\pi/2}_{0} \frac{sin^{2009}x}{sin^{2009}x + cos^{2009}x}[/tex]

I used the identity [tex]cos^{2}= 1 - sin^{2}[/tex], but instead I set the exponent as 2009. And so I ended up with the answer being -1. I'm just wondering whether this is a legal solution or am I not allowed to do that. Thanks.

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# Homework Help: Sin and Cos Integrals

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