- #1
CrossFit415
- 160
- 0
Ok...
(2, -3)
R = (Sqrt x^2 + y^2)
R = (sqrt (2)^2 + (-3)^2)
R= (sqrt 13)^2
R=13
Sin = y/r
Sin -3 / 13 ?
Cosin 2 / 13 ?
But then.. how come the answer gives me sin -3 (sqrt13) / 13 and for cosin 2(sqrt13) / 13
My question is how come there's a (sqrt13) included for the numerator since r = 13 ?
(2, -3)
R = (Sqrt x^2 + y^2)
R = (sqrt (2)^2 + (-3)^2)
R= (sqrt 13)^2
R=13
Sin = y/r
Sin -3 / 13 ?
Cosin 2 / 13 ?
But then.. how come the answer gives me sin -3 (sqrt13) / 13 and for cosin 2(sqrt13) / 13
My question is how come there's a (sqrt13) included for the numerator since r = 13 ?
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