1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Sin x tranformation

  1. Apr 4, 2007 #1
    Describe fully the sequence of two transformations that maps the graph y = sinx onto the graph of y = 3sin2x

    Well I know that when x = 45 y = 3, when x = 90 y = 0 when x = 135 y = -3 and so on, but tranformations and translation (move), reflection, rotation and englargment. I would presume that the graph is enlarged and then relected, however what is the point of enlargment?

    Am I right so far?

    Thanks
    :biggrin:
     
    Last edited: Apr 4, 2007
  2. jcsd
  3. Apr 4, 2007 #2

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    Actually, you don't know that- or shouldn't. When sine and cosine are used as functions, rather than to solve functions, the basic definitions require that arguments be interpreted as in radians. (Strictly speaking a mathematician wouldn't think of the argument as an angle at all, but calculators are designed by engineers who do!) What you should know is that when [itex]x= \pi/4[/itex], y= 3, when [itex]x= \pi/2[/itex], y= 0, etc.

    I'm not sure what you mean by "point of enlargement"- the "enlargement" is uniform along the axes. Your "base function" is sin(x). I prefer to think that anything done after the base function is a change in y, anything done before is a change is x. Here,you multiply x by 2 before taking the sine, then multiply by 3. Okay, multiplying y by 3 stretches (enlarges) the y value (height of the graph) by 3. Multiplying x by 2 before taking sine changes the graph horizontally. Normally, a sine graph goes from 0 to 0 as x changes from 0 to [itex]\pi[/itex]. Here, that happens as 2x changes from 0 to [itex]\pi[/itex]- in other words as x changes from 0 to [/itex]\pi/2[/itex]. Horizontally, the graph is "shrunk" by 1/2. There is no reflection- that would involve multiplying by -1.
     
  4. Apr 4, 2007 #3
    [​IMG]
    part B. How would you answer that? At GCSE, weve never used sin with pi
     
  5. Apr 4, 2007 #4

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    Yeah, I see that. I don't like but I will try to live with it!

    But I told you the transformations are a stretch by a factor of 3 vertically and a "squeeze" by a factor of 1/2 horizontally.
     
  6. Apr 4, 2007 #5
    Will that get me the marks in the exam? (it's GCSE)

    Thanks
     
  7. Apr 4, 2007 #6
    Technically, since it's a sine function you'd need to put that it has an amplitude of 3 instead of 1, and it's period is changed from [tex]2\pi[/tex] (or 360 degrees) to [itex]\pi[/itex] (or 180 degrees).

    This is for part "b" I mean.
     
    Last edited: Apr 4, 2007
  8. Apr 5, 2007 #7

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    Those statements are true about the graph, but they are not "transformations" and the problem specifically said "describe the sequence of transformations".

    As to whether "Will that get me the marks in the exam?" I have no idea! That is how I would answer the question as asked.
     
  9. Apr 7, 2007 #8
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Sin x tranformation
  1. Sin(x/2) = x/4 (Replies: 4)

  2. Sin(x) + cos(x) (Replies: 4)

  3. Sin(arctan(x/4))= ? (Replies: 4)

Loading...