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## Main Question or Discussion Point

When I worked this problem, I came up with the following:

sin 11pi/12= -sq root 2/4 (sq root3-1)

cos 11pi/12= -sq root 2/4 (sq root3+1)

tan 11pi/12= 2-sq root3

am I far off?

sin 11pi/12= -sq root 2/4 (sq root3-1)

cos 11pi/12= -sq root 2/4 (sq root3+1)

tan 11pi/12= 2-sq root3

am I far off?