- #1
Ry122
- 565
- 2
in bsin30-85.7sin(theta)=0
How can I make theta the subject?
How can I make theta the subject?
It's the inverse.Ry122 said:how is that done?
I think what you did was implied something like ... [tex]\frac{1}{x}=x^{-1}[/tex]Ry122 said:so is this correct
sin(theta)=-bsin30/-85.7
1/sin(theta)=(-85.7)/(-binsin30)
sin^-1(-bsin30/-85.7)=(theta)
Ry122 said:so is this correct
sin(theta)=-bsin30/-85.7
1/sin(theta)=(-85.7)/(-binsin30)
sin^-1(-bsin30/-85.7)=(theta)
The equation "bsin30-85.7sin(theta)=0" is used to solve for the value of theta, which is an angle in a right triangle, given the value of b and other trigonometric functions.
To solve for theta, you can use the trigonometric identity sin(a-b)=sin(a)cos(b)-cos(a)sin(b) to rewrite the equation as bsin(30)-85.7sin(theta)=0. Then, you can use the inverse sine function to isolate theta and solve for its value.
The variable b represents the length of the side opposite to the angle theta in a right triangle.
Yes, this equation can be solved without a calculator by using trigonometric identities and solving for theta algebraically.
The range of possible values for theta in this equation is from 0 to 180 degrees or 0 to π radians, as these are the possible values for an angle in a right triangle.