Two ropes are attached to a log that is floating in the water. A force of 80.0 N is applied to one rope and a force of 60.0 N is applied to the other rope, which is lying at an angle of 40° from the first rope. What is the net force on the log?
We know that the angle between the two known vectors is 140°.
The Attempt at a Solution
Now to find the angle between the resultnt force vector and the 80.0 N vector, use sine law
sinA/a = sinB/b = sinC/c
sinA/60.0 N = sin140°/132 N
sinA/60.0 N x 60.0 = sin140/132 x60.0
sinA =sin140/132 x 60.0
sinA = 0.292176186
would that be correct??