As far as i can see it doesn't say anything about phase shift so does that mean it doesn't affect anything?
#4
Naty1
5,607
40
wt is the phase shift
see http://en.wikipedia.org/wiki/Phase_(waves [Broken])
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#5
marla11
3
0
I'm sorry but I'm still confused. If y1 = Asin(kx-wt+phi) and y2 = Asin(kx+wt)
the addition is y= 2Acos(wt-phi/2)sin(kx+phi/2) where phi is the phase shift between 0 and 2pi. Does this still fit the standing wave equation y=(2Asin(kx))cos(wt) meaning its a standing wave or does the difference in phase shift mean they do not create a standing wave?
#6
Bob S
4,662
6
You have one forward-traveling wave (wt-kx) and one backward wave (wt+kx) of the same amplitude, which is a standing wave. My CRC Math Tables (10th Ed, 1954) on page 345 shows the sum
sin(x) + sin(y) = 2·sin[(x+y)/2]·cos[(x-y)/2]
Bob S
#7
meichenl
25
0
Marla,
Your equations will be easier to read if you typeset them in LaTeX.
Yes, the equation you give is a standing wave. If you start with