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Sine wave problem

  1. Sep 18, 2007 #1
    I have a question that says: prepare a table of values and plot the graph for the domain (-pie,pie) for the function f(x)=2sin(2x)

    I understand how to do that for y=sinx, but for this function the wave compresses horizontally and stretches vertically so isnt the domain now (-pie/2,pie/2) and then therefore how can you make a table of values for (-pie,pie).

    thanks for any help
    andrew
     
  2. jcsd
  3. Sep 18, 2007 #2

    Dick

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    No, the domain is still (-pi,pi). Just use a calculator.
     
  4. Sep 18, 2007 #3
    why is that because doesnt the 2x compress it horizontally?
     
  5. Sep 18, 2007 #4

    Dick

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    Yes, the period will be cut in half, but you can still put x=pi, f(x)=2*sin(2*pi) in your table.
     
  6. Sep 18, 2007 #5

    HallsofIvy

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    The period is now [itex][-\pi /2, \pi /2][/itex]. The "domain" is still all real numbers just as it is for sin(x).
     
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