A single slit is illuminated with 630 nm light, and the resulting diffraction pattern is viewed on a screen 2.8 m away.
If the linear distance between the first and second dark fringes of the pattern is 12 cm, what is the width of the slit?
W = [tex]\lambda[/tex] m / sin [tex]\theta[/tex]
The Attempt at a Solution
theta = arctan (.12/2.8) = 2.45
W = 630 x 10^-9 x 2 / sin 2.45