# Single Slit Question

1. May 24, 2010

### MetsFan09

1. The problem statement, all variables and given/known data
A single slit is illuminated with 660 nm and the resulting diffraction pattern is viewed on a screen 2.3 m away.
a. If the linear distance between the 1st and 2nd dark fringes of the pattern is 12 cm. What is the width of the slit?

2. Relevant equations
W(X/L) = m(lambda)

3. The attempt at a solution
W(.012m/.0023m = 1(660x 10^-9)
W = 1.27 x 10^-7

Someone else tells me thats wrong and that I have to divide the linear distance by two to get 6 cm instead of 12. Is this true? And if so why? I really don't understand why we would have to do that.

2. May 24, 2010

### ehild

Explain me the meaning of the letters in the equation you used, please.

ehild

3. Sep 4, 2010

### labview1958

What happens to the distance between fringes as the width of the single slit become larger? Does the distance between fringes increases? What happens to the centre bright fringe? Does it become larger with an increasing single slit width? My hunch is: Increasing the width increases the size of the bright central fringe, but applets on the net show otherwise. Can someone help?

4. Sep 4, 2010

### ehild

It is a single slit, so a pair of rays which cancel each other come out from the same slit. For a dark fringe, each rays emerging from the slit has to get an other one to cancel with. So the angles at which a dark fringe occurs are those for which

W/2 sin(α)=(2m+1)λ /2 ---->W sin(α)=(2m+1)λ

If the screen is at distance L from the slit and the fringe is at distance X from the centre, tan(a)=X/L, but tan(α)=sin(α) for small angles, so

W *X/L=(2m+1)λ , (m=0,1,2....)

for the dark fringes.

Find X for the first and second dark fringes and see what happens if the width of the slit W increases.

ehild

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