Singularities and Kasner solution

  • #1
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Homework Statement


Investigate the possible behaviour of the singularity as [tex]t \rightarrow 0[/tex] in the Kasner solution.


Homework Equations


The metric for the Kasner solution is given by

[tex]ds^2 = c^2dt^2 - X_1^2(t)dx_1^2 - X_2^2(t)dx_2^2 - X_3^2(t)dx_3^2[/tex]


The Attempt at a Solution


I have no clue...
 

Answers and Replies

  • #2
Dick
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Try writing down a more specific form of the Kasner soln. The spatial metric functions can be written as powers of t. What are the conditions on the exponents coming from Einsteins eqns?
 
  • #4
Dick
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You can't do anything with the metric as written - it's too general. What ARE X_1,X_2 and X_3 in the Kasner soln. You may have to look it up...
 
  • #5
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All I can find about this is that substituting the metric into the Einstein equations gives

[tex]\frac{\ddot{X}_i}{X_i} - \left(\frac{\dot{X}_i}{X_i}\right)^2 +3\left(\frac{\dot{X}_i}{X_i}\right)\left(\frac{\dot{a}}{a}\right) = \frac{4\pi G}{c^4}\left(\rho - \frac{p}{c^2}\right)[/tex]

in which [tex]a^3 = X_1X_2X_3[/tex].
 
  • #6
Dick
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That's a start. You shouldn't have a loose index i floating around though. Assuming you can get the correct Einstein equations (and there should be two), Kasner is a vacuum solution, so put rho=p=0. Put X_i=t^p_i. Turn this into equations in the constants p_i. Are you supposed to actually derive Kasner or just describe it's properties? It might be a good idea to just look up the solution to see what you are aiming for.
 
  • #7
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I think I'm just supposed to describe the behaviour of the singularity. I don't like this book, it has too many errors. ;) Why should I use [tex]X_i = t^{p_i}[/tex]? According to my book this is a perfect fluid model.
 
  • #8
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Ok, I found that this is a particulary simple behaviour. Also

[tex]\frac{\dot{X}_1 \dot{X}_2}{X_1X_2} + \frac{\dot{X}_2 \dot{X}_3}{X_2X_3} + \frac{\dot{X}_3 \dot{X}_1}{X_3X_1} = \frac{8 \pi G}{c^4}\rho[/tex]

Putting in [tex]X_i = t^{p_i}[/tex] and using [tex]\rho=0[/tex] gives me

[tex]0 \propto \frac{1}{t^2}[/tex]

Is this true?
 
  • #9
Dick
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It gives you an algebraic condition on the p's that must vanish. What is it? Again there is another Einstein equation. It will give you another algebraic condition.
 
  • #10
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So [tex]p_1p_2 + p_2p_3 + p_3p_1 = 0[/tex]?
I also got that

[tex]\frac{\dot{a}}{a} = \frac{1}{3} \left( \frac{\dot{X}_1}{X_1} + \frac{\dot{X}_2}{X_2} + \frac{\dot{X}_3}{X_3} \right)[/tex]

but then I get some a aswell..?
 
  • #11
Dick
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That is one alright. Since we are not actually trying to derive this you should find

[tex]p_1+p_2+p_3=1[/tex] and
[tex]{p_1}^2+{p_2}^2+{p_3}^2=1[/tex].
 
  • #12
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Yeah that I got..
 
  • #13
Dick
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Good. So there are actually lots of Kasner solutions corresponding to different values of the p's. Find a specific example and describe it's behavior.
 
  • #14
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Well, what I don't understand is HOW to describe it's behaviour.
 
  • #15
Dick
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Ok, here's a set of p's.

[tex]p_1=1/3, p_2=(1+\sqrt{3})/3, p_3=(1-\sqrt{3})/3[/tex]

How would you describe this behavior as t->0?
 
  • #16
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Well, I will always get

[tex]\frac{\dot{a}}{a} = \frac{1}{3t}[/tex]

so for [tex]t \rightarrow 0[/tex]

[tex]\dot{a} \rightarrow \infty[/tex]
 
  • #17
Dick
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Sure. But describe qualitatively the behavior of the scale factors themselves (the X_i's).
 
  • #18
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Sorry, I don't know what to say about them.
 
  • #19
Dick
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That's ok. In a matter dominated universe (a=t^(2/3), I think) a->0 as t->0. Is that true here?
 
  • #20
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Humm, if I solve

[tex]\frac{\dot{a}}{a} = \frac{1}{3t}[/tex]

I get

[tex]a = t^{1/3} \rightarrow 0[/tex]

for [tex]t \rightarrow 0[/tex].

But if I use [tex]a_0[/tex] instead, I get

[tex]a = a_0 \frac{1}{3} ln(t) \rightarrow - \infty[/tex].
 
  • #21
Dick
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You don't have to solve a DE for the scale factors. You already did that. a_i=t^p_i. Where the p_i's are what I sent you a few posts back. Note there are three different scale factors - the universe is anisotropic. And, hint, one of the scale factors is not like the others.
 
  • #22
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I don't get it. What about [tex]t \rightarrow 0[/tex]?
 
  • #23
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And how do I get [tex]a_i = t^{p_i}[/tex]?
 
  • #24
Dick
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And how do I get [tex]a_i = t^{p_i}[/tex]?
Huh? It's a Kasner solution. The scale factors are t^p1, t^p2 and t^p3. I sent you a sample set of p's. What's the behavior of each as t->0?
 
  • #25
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Well then every [tex]a_i \rightarrow 0[/tex] as for the matter dominated universe.
 

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