# Sinh / sin

1. May 16, 2016

### struggles

1. The problem statement, all variables and given/known data
So this is a really simple problem and i know I'm missing something really obvious but i just can't spot it.

2. Relevant equations

3. The attempt at a solution
so in the second part above I get :
e-x - ex/2i. However I don't get the next bit as the 2i on the denominator is now factored into the top equation to give -ie-x + iex/2. I don't get how the 2 equations are equivalent and what they've done to get the i from the denominator to the numerator. If anyone could explain how this happened that'd be great!

2. May 16, 2016

### Staff: Mentor

What is i?

3. May 16, 2016

### axmls

Do you know what $1/i$ is?

4. May 16, 2016

### struggles

i-1?

5. May 16, 2016

### Staff: Mentor

First answer my question and then use it to answer struggles'. $i^{-1}$ is simply another form of $\frac{1}{i}$ which doesn't really help.

6. May 16, 2016

### robphy

Suppose you didn't know what $i$ is
but it seems that (from your second equals sign) $\frac {1}{i}= -i$... what must $i$ satisfy?

7. May 16, 2016

### Staff: Mentor

How is it defined? What stands $i$ for? There must have been some explanation for it.
Remark: Sorry, for confusing your names, struggles and axmls!

8. May 16, 2016

### axmls

Though it isn't obvious that this is the way to find this, here's a hint:
$$\frac{1}{i} = \frac{1}{i} \frac{i}{i}$$

9. May 16, 2016

### struggles

so i = √-1 so i2 = -1. so 1/i must equal 1/(-1)1/2 = (-1)-1/2? is that what you were getting at fresh-_42?
So axmls 1/i = i/i^2 = -i! Thanks both of you!