According to Hooke's law [itex] F = k \delta x [/itex], and the energy stored in a certain configuration is [itex] E = \frac{1}{2} k (\delta x)^2 [/itex](adsbygoogle = window.adsbygoogle || []).push({});

But it just so happens that this last formula is only valid if one of the ends of this spring if fixed. I would like to know the following:

What is the elastic energy stored in a spring with natural lengh 1 meter which is performing a sinusoidal oscillation of amplitude (peak to peak) 2 meters and elastic constant equal do 10 N / m.

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# Sinusoidally oscillating spring

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