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Forums
Physics
Classical Physics
Siphoning through a straight tube
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[QUOTE="jack action, post: 5510416, member: 240508"] The pressure at the bottom of the tube due to the weight of the nitrogen will be ##\rho g h## or 0.11875 bar. Adding the atmospheric pressure, you get an absolute pressure of 1.132 bar. If you maintain a pressure inside the dewar larger than this, the nitrogen will flow out the tube. At the beginning of the process (when the difference in height is 1 m), you only need 1.092 bar of absolute pressure in the dewar to initiate flow outside of the tube. [/QUOTE]
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Siphoning through a straight tube
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