Sketch the following regions and state the interior and the closure:
The Attempt at a Solution
a) z=x+iy so |x+iy-2+i|-> |(x-2)+i(y+1)|≤1
So it would just be a circle on the real plane? And the interior would be the equation with < instead of ≤ right? I'm not sure how to write the closure though.
b)Im(z)= y so it would be a straight line at y=1 on the real plane and there is no interior or closure since it is an open set right?