1. The problem statement, all variables and given/known data Sketch the following regions and state the interior and the closure: a) |z-2+i|≤1 b) Im(z)>1 2. Relevant equations z=x+iy 3. The attempt at a solution a) z=x+iy so |x+iy-2+i|-> |(x-2)+i(y+1)|≤1 So (x-2)2+(y+1)2≤1 So it would just be a circle on the real plane? And the interior would be the equation with < instead of ≤ right? I'm not sure how to write the closure though. b)Im(z)= y so it would be a straight line at y=1 on the real plane and there is no interior or closure since it is an open set right?