- #1

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## Homework Statement

Sketch (x+y+3)^2 + (x-y-3)^2 = 0

## Homework Equations

## The Attempt at a Solution

How?? I have totally no idea.

- Thread starter elitewarr
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- #1

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Sketch (x+y+3)^2 + (x-y-3)^2 = 0

How?? I have totally no idea.

- #2

Mentallic

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- #3

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For that matter, think about [itex]a^2+b^2=0[/itex]

- #4

Mentallic

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Haha that's a much more effective methodFor that matter, think about [itex]a^2+b^2=0[/itex]beforeyou expand the terms.

- #5

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Let a be x, b be y+3

(a+b)^2 + (a-b)^2 = 0

2a^2 + 2b^2 = 0

(x)^2 + (y+3)^2 = 0

But if I bring x^2 over,

(y+3)^2 = -x^2

I doubt there is such curve and if there is, it is undefined isn't it?

thanks for the reply.

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Ok. So, (0,-3) is the only value? Is the graph just a dot?

Thanks.

Thanks.

- #8

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Yes. Also note that in your original equation:Ok. So, (0,-3) is the only value? Is the graph just a dot?

Thanks.

(x+y+3)

both terms must be zero, so the intersection of the two lines:

x+y+3=0 and x - y - 3 = 0

is the only point which satisfies the equation. This agrees with your answer.

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