Sketch the curve z = x2 + 2y2
The Attempt at a Solution: [/B]The easiest thing to do is to sketch the traces at x, y and z = 0. I'm 95% sure its an elliptic paraboloid, but the 2 in front of the Y is really throwing me off. Should we divide everything by 2 and have an ellipse with a radius of √2 and 1? If thats the case then when we set Y to 0 ( for example ) we get z = 2x2 and were right back where we started....Im kinda lost here.
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