Q 1. How fast will a skydiver be traveling 1 second after jumping from a plane?
The Attempt at a Solution
I guessed the answer to be 10 m/s because something to do with gravity and a 1 kg mass. The answer is correct according to the book but I’m not sure why. The mass of the skydiver will be much more than 1 kg. So my guess is not really an educated guess.
Please can you explain to me the answer in words terms (without the use of equations). (If possible) Thank you.
I recently learned about the SUVAT formula from another post recently so have applied this here. (Please note that the book I’m reading does not even mention SUVAT formula yet so I don't think I meant to be using SUVAT)
s = distance
u = initial velocity
v = final velocity
a = acceleration
t = time
v = u + at
V = 0 + 10*1 (I am assuming acceleration to be 10m/s2 because of gravity)
V = 10m/s (The answer is correct according to the book)
I’d like to post the second part of this question here too, if I may because it is linked to the first question.
Q 2. If the air resistance force on the skydiver is 0.1V2, what will be its magnitude and direction after one second?
Here I have no idea where to start. Please note this section of the book is discussing terminal velocity (if that has any relevance).
Answer in the book is 15 N upwards