When the parachute is fully open, the effective drag coefficient of the sky diver plus parachute increases to 60.0 kg/m. What is the drag force F_drag acting on the sky diver immediately after she has opened the parachute? i know that F_drag = Dv^2 here D is given which is 60 kg/m. and i found v by the equation v= square root of ((m.g)/D) so i got 13.06 for V^2 and then i put the values in the equation F_drag = D.V^2 = 783. 6 is this right?